First note that the table provides values \(h(x)\) for inputs \(x\) that get reasonably close to \(3\text{:}\) from the left, we have the sequence of inputs \(2.9, 2.99, 2.999\text{,}\) and from the right we have the sequence \(3.1, 3.01, 3.001\text{.}\) The closest inputs included in the table are \(2.999\) and \(3.001\text{,}\) which are a distance of
\begin{equation*}
.001=\abs{3.0001-3}=\abs{2.999-3}
\end{equation*}
away from \(3\text{.}\) Moreover, we notice that as these inputs get closer to \(3\text{,}\) the outputs \(h(x)\) seem to approach a value between \(0.142\) and \(0.143\text{.}\) Thus, we are inclined to believe that the limit \(\lim\limits_{x\to 3}h(x)\) does indeed exist, and that
\begin{equation*}
0.142 \leq \lim\limits_{x\to 3}h(x) \leq 0.143 \text{.}
\end{equation*}
In fact, since the values \(h(x)\) decrease as \(x\) approaches from the left, and increase as \(x\) approaches from the right, we might further guess that
\begin{equation*}
0.14273 \leq \lim\limits_{x\to 3}h(x) \leq 0.14298\text{.}
\end{equation*}
Notice, however, that that guess would be conditioned on the assumption that \(h\) is decreasing for all \(x\) sufficiently close to \(3\) on the left, and all \(x\) sufficiently close to \(x\) on the right; and this is an assumption we are not in a position to verify at the moment.