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Section 2.4 Hamilton quaternion rings

Specimen 26. Quaternion rings.

Let \(R\) be a nontrivial commutative ring, and assume \(1+1\ne 0\) in \(R\text{.}\) We define \(H(R)\) to be the set of all formal sums
\begin{gather*} a_1+a_2i+a_3j+a_4k\text{,} \end{gather*}
where \(a_i\in R\) for all \(1\leq i\leq 4\text{.}\) We define addition on \(H(R)\) as
\begin{gather*} (a_1+a_2i+a_3j+a_4k)+(b_1+b_2i+b_3j+b_4k) \\ = (a_1+b_1)+(a_2+b_2)i+(a_3+b_3)j+(a_4+b_4)k\text{.} \end{gather*}
We define multiplication to be the unique binary operation \(\cdot\) that distributes over the addition operation \(+\text{,}\) satisfies
\begin{align} b(a_1+a_2i+a_3j+a_4k) \amp =(a_1+a_2i+a_3j+a_4k)b \tag{2.4.1}\\ \amp =ba_1+ba_2i+ba_3j+ba_4k\tag{2.4.2} \end{align}
for all
\begin{align*} b \amp =b+0i+0j+0k\in H(R)\text{,} \end{align*}
and satisfies
\begin{align} i^2\amp =j^2=k^2=-1 \tag{2.4.3}\\ ij \amp = -ji= k\tag{2.4.4}\\ jk \amp = -kj= i\tag{2.4.5}\\ ki \amp = -ik= j\text{.}\tag{2.4.6} \end{align}
The triple \((H(R), +, \cdot)\) is a ring called the Hamilton quaternion ring over (or with coefficients in) \(R\).
In the special case where \(R=\R\text{,}\) we denote \(\HH=H(\R)\) and call \(\HH\) simply the Hamilton quaternions.

Definition 2.4.1. Quaternion conjugation and norm.

Let \(R\) be a nontrivial commutative ring. Given \(q=a_1+a_2i+a_3j+a_4k\in H(R)\text{,}\) its quaternion conjugate, denoted \(\overline{q}\) is defined as
\begin{align} \overline{q} \amp =a_1-a_2i-a_3j-a_4k\text{.}\tag{2.4.7} \end{align}
The quaternion norm is the function \(N\colon H(R)\rightarrow R\) defined as
\begin{gather} N(q)=\overline{q}q\text{.}\tag{2.4.8} \end{gather}
A straightforward computation shows that if \(q=a_1+a_2i+a_3j+a_4k\text{,}\) then
\begin{align*} N(q) \amp =a_1^2+a_2^2+a_3^2+a_4^2\text{.} \end{align*}

Proof.

Proof.

For \(q=a_1+a_2i+a_3j+a_4k\in \HH\text{,}\) we have
\begin{align} q\ne 0 \amp \iff a_i\ne 0 \text{ for some } i \tag{2.4.9}\\ \amp \iff a_1^2+a_2^2+a_3^2+a_4^2\ne 0 \amp (a_i^2> 0 \iff a_i\ne 0)\tag{2.4.10}\\ \amp \iff N(q)\ne 0\tag{2.4.11}\\ \amp \iff N(q)\in \R^*\tag{2.4.12}\\ \amp \iff q\in \HH^*\text{.}\tag{2.4.13} \end{align}
Thus \(\HH^*=\HH-\{0\}\text{,}\) as desired.

Remark 2.4.4. Division rings over \(\R\).

We have met our first noncommutative division ring in the form of \(\HH\text{.}\) More than just a ring, \(\HH\) is what we call an \(\R\)-algebra, which we can understand as a ring containing a β€œcopy” of \(\R\) lying in its center. Any \(\R\)-algebra \(A\) is in particular a vector space over \(\R\text{:}\) we define vector addition as the ring addition, and we define scalar multiplication as the ring multiplication \(ra\text{,}\) where \(r\in \R\) and \(a\in A\text{.}\)
Let’s call a division ring that is also an \(\R\)-algebra a division algebra over \(\R\text{.}\) Besides \(\HH\text{,}\) note that \(\R\) and \(\C\) are also division algebras over \(\R\text{.}\) Are there any others? The answer is no, if we further stipulate that the division algebra have finite dimension over \(\R\text{.}\) This is a famous result due to Frobenius: if \(A\) is a finite-dimensional division algebra over \(\R\text{,}\) then \(A\) is isomorphic to \(\R\text{,}\) \(\C\text{,}\) or \(\HH\text{!}\) (Of course, β€œisomorphism” is yet to be definied, but you can imagine what this will mean for rings.)

Remark 2.4.5. Finite division rings.

While we are hunting for interesting examples of division rings, you might also wonder whether there are any interesting finite division rings. The answer here is similarly constrictive. A famous result due to Wedderburn states that every finite division ring is in fact a finite field! Thus there are no noncommutative finite division rings. Moreover, it is not very difficult to describe all finite fields, as you will see in Math 331-3.